Browse · MATH Print → jmc number theory intermediate Problem Express 2138−1427 as a base 10 integer. Solution — click to reveal We have that 21381427=2(82)+1(81)+3(80)=2(64)+1(8)+3(1)=128+8+3=139=1(72)+4(71)+2(70)=1(49)+4(7)+2(1)=49+28+2=79So, 2138−1427=139−79=60. Final answer 60 ← Previous problem Next problem →