smc

By the rational root theorem, $1,-1,2,-2,3,-3,6,-6$ are possible rational roots. Because $x^3+6x^2+11x+6>0$ for $x>0$, so there are no positive roots. We try $-1,-2,-3,-6$, so $x=-1,x=-3,x=-2$, so there are no positive real roots; $\boxed{\text{no positive real roots}}$