jmc

Since $SUR$ is a straight line, then $\angle RUV=180^{\circ }-\angle SUV=180^{\circ }-120^{\circ }=60^{\circ }$.

Since $PW$ and $QX$ are parallel, then $\angle RVW=\angle VTX=112^{\circ }$.

Since $UVW$ is a straight line, then $\angle RVU=180^{\circ }-\angle RVW=180^{\circ }-112^{\circ }=68^{\circ }$.

Since the measures of the angles in a triangle add to $180^{\circ }$, then $$\angle URV=180^{\circ }-\angle RUV-\angle RVU=180^{\circ }-60^{\circ }-68^{\circ }=\boxed{52^{\circ }}.$$