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prealgebra intermediate

Problem

(\frac{1}{4})^{- \frac{1}{4}} =

(A)

- 16

(B)

- 2

(C)

- \frac{1}{16}

(D)

\frac{1}{256}

(E)

2

Solution

(\frac{1}{4})^{- \frac{1}{4}} = 4^{\frac{1}{4}} = 44 = 4 = 2

which is

2

Final answer

E