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jmc

prealgebra intermediate

Problem

There are four positive integers that are divisors of each number in the list Find the sum of these four positive integers.
Solution
We will begin by finding all the positive factors of , which are the same as the positive factors of . The positive factors of 12 are 1, 2, 3, 4, 6, and 12. The four numbers we seek must be among these six numbers.

Note that the number is not a factor of each number on the list, since dividing by gives a remainder of . We also know that cannot be a factor of , since dividing by gives a remainder of . However, is a factor of each number on the list, since Since , , , and are factors of , and is a factor of each number on the list, , , , and must be a factor of each number on the list. So these are the four numbers we were looking for, and our final answer is
Final answer
12