jmc

Problem 5. Let's call the side length of the square $s$. This makes the perimeter of the square $4s$, which we know is 144 units. Solving $4s=144$ for $s$, we get $s=36$. We also can say that the perimeter of each rectangle is $2(s+0.25s)$. Since we found that $s=36$, we know that the perimeter of each rectangle is $2(36+(0.25)(36))=\boxed{90\text{ units}}$.