smc

Break up the absolute value into two cases. For the first case, let $x<5$, so $\frac{5-x}{3}$ is positive. That means (for $x<5$) $$\frac{5-x}{3}<2$$ $$5-x<6$$ $$-x<1$$ $$x>-1$$ For the second case, let $x\ge 5$, so $\frac{5-x}{3}$ is negative. That means (for $x\ge 5$) $$\frac{x-5}{3}<2$$ $$x-5<6$$ $$x<11$$ Combine both cases to get $-1<x<11$, which is answer choice $\boxed{-1<x<11}$.