Browse · MATH Print → jmc algebra intermediate Problem Positive real numbers r,s satisfy the equations r2+s2=1 and r4+s4=87. Find rs. Solution — click to reveal We have 2r2s2=(r4+2r2s2+s4)−(r4+s4)=(r2+s2)2−(r4+s4)=(1)2−87=81, so r2s2=161. This means that rs=41. Final answer \frac{1}{4} ← Previous problem Next problem →