imc

The sum of two angles in a triangle is $\frac{6}{5}$ of a right angle $⟶\frac{6}{5}\times 90=108$ If $x$ is the measure of the first angle, then the measure of the second angle is $x+30$. $$x+x+30=108⟶2x=78⟶x=39$$ Now we know the measure of two angles are $39^{\circ }$ and $69^{\circ }$. By the Triangle Sum Theorem, the sum of all angles in a triangle is $180^{\circ },$ so the final angle is $72^{\circ }$. Therefore, the largest angle in the triangle is $\boxed{72}$