Browse · MATH Print → jmc algebra junior Problem The expression 2z2+13z+21 can be written as (z+a)(2z+b), where a and b are integers. What is 2a+b? Solution — click to reveal We see that 2z2+13z+21=(z+3)(2z+7), thus a=3 and b=7. Hence, 2a+b=13. Final answer 13 ← Previous problem Next problem →