jmc

There are $\left(\genfrac{}{}{0ex}{}{15}{2}\right)=105$ ways for Michael to choose two of the 15 kinds of fruits, and there are $\left(\genfrac{}{}{0ex}{}{10}{3}\right)=120$ ways for Michael to choose three of the 10 kinds of soup. Therefore, there are $105\cdot 120=\boxed{12600}$ ways for Michael to choose fruit and soup.