Browse · harp Print → smc prealgebra senior Problem What is 10⋅(21+51+101)−1? (A) 3 (B) 8 (C) 225 (D) 3170 Solution — click to reveal We have 10⋅(21+51+101)−1 Making the denominators equal gives ⟹10⋅(105+102+101)−1 ⟹10⋅(105+2+1)−1 ⟹10⋅(108)−1 ⟹10⋅(54)−1 ⟹10⋅45 ⟹450 Finally, simplifying gives ⟹225 Final answer C ← Previous problem Next problem →