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Belorusija 2012

Belarus 2012 counting and probability

Problem

Six teams take part in a football tournament. Each team plays exactly one game with any other team. A team receives 3 points for a win, 1 point for a draw, and 0 point for a loss. After the tournament is over, the teams have 10, 9, 6, 6, 4, and 2 points.

a) Prove that the team taking the second place (i.e. having 9 points) does not lose the game with the team winning the first place (i.e. having 10 points).

b) Is it possible uniquely to determine the result of the game between the teams taking the second and the first places?
Solution
The following tables contain all possible results of the tournament.
Wins0000011111
Draws0123450123
Losses5432104321
Points0123453456
Wins2222333445
Draws0123012010
Losses3210210100
Points678991011121315
We see that the first team getting 10 points and having the first place wins 3 games, loses 1 game, and ends 1 game in a draw; so this team has 4 effective games. If the second team getting 9 points and having the second place loses the game with the first team, then it wins 3 games and loses 2 games, i.e. 5 of its games are effective. Therefore the total number of effective games of the first and the second teams is equal to 9, but only one of these games is common. So there are at least 8 effective games in the tournament, which contradicts the equality . Hence, the second team does not lose the game with the first team.

b) There are tournaments with distinct results (see the tables).

Nº1Nº2Nº3Nº4Nº5Nº6Σ
Nº10333110
Nº2311139
Nº3011136
Nº4011136
Nº5011114
Nº6100012
Table 1

Nº1Nº2Nº3Nº4Nº5Nº6Σ
Nº11033310
Nº2131139
Nº3301116
Nº4011136
Nº5011114
Nº6001012
Table 2
Final answer
a) The second-place team did not lose to the first-place team. b) No; the result is not uniquely determined.

Techniques

Counting two waysInvariants / monovariants