Browse · MATH Print → jmc algebra junior Problem The line y=23x−25 is parameterized by (x,y)=(f(t),15t−7). Enter the function f(t). Solution — click to reveal Let y=15t−7. Then 15t−7=23x−25.Solving for x, we find x=10t+12. Final answer 10t + 12 ← Previous problem