Browse · MATH Print → jmc algebra intermediate Problem If x5+5x4+10x3+10x2−5x+1=10,and x=−1, compute the numerical value of (x+1)4. Solution — click to reveal Adding 10x to both sides, we get x5+5x4+10x3+10x2+5x+1=10x+10.Then (x+1)5=10(x+1). Since x+1=0, we can divide both sides by x+1, to get (x+1)4=10. Final answer 10 ← Previous problem Next problem →