Express 24911+3AB12 as a base 10 integer. Here A and B denote the digits whose values are 10 and 11, respectively, in base 12.
Solution — click to reveal
We have that 249113AB12=2(112)+4(111)+9(110)=2(121)+4(11)+9(1)=242+44+9=295=3(122)+10(121)+11(120)=3(144)+10(12)+11(1)=432+120+11=563So, 24911+3AB12=295+563=858.