Browse · MATH Print → jmc algebra intermediate Problem If x−y=15 and xy=4, what is the value of x2+y2? Solution — click to reveal Squaring both sides of the first equation, we get that x2−2xy+y2=225. So, we know that x2+y2=225+2xy. Since xy=4, we find x2+y2=225+2(4)=233. Final answer 233 ← Previous problem Next problem →