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jmc

algebra intermediate

Problem

Evaluate

(\frac{- 2 i}{5})^{2}

.

Solution

(\frac{- 2 i}{5})^{2} = (\frac{( - 2 i ) ^{2}}{5 ^{2}}) = (\frac{( - 2 ) ^{2} i ^{2}}{25}) = - \frac{4}{25} .

Final answer

-\dfrac{4}{25}