If (log3x)(logx2x)(log2xy)=logxx2, then y equals:
(A)
9/2
(B)
9
(C)
18
(D)
27
Solution — click to reveal
From the properties of logarithms, we can simplify the equation and solve for y: (log3x)(logx2x)(log2xy)(log32x)(log2xy)log3yyy=logxx2=2logxx=2=32=9 Thus, our answer is 9.