Browse · harp Print → jmc prealgebra junior Problem What is the value of 4⋅(−1+2−3+4−5+6−7+⋯+1000)? (A) −10 (B) 0 (C) 1 (D) 500 (E) 2000 Solution — click to reveal We group the addends inside the parentheses two at a time: −1+2−3+4−5+6−7+…+1000=(−1+2)+(−3+4)+(−5+6)+…+(−999+1000)=500 1’s1+1+1+…+1=500. Then the desired answer is 4×500=2000. Final answer E ← Previous problem Next problem →