smc

Taking the logarithm in base $3$ of both sides, we get $x+3={\log }_{3}135$. Using the property $\log ab=\log a+\log b$, we get $x+3={\log }_{3}5+{\log }_3{3}^3$, or $x={\log }_{3}5$. Converting into base $10$ gives $x=\frac{\log 5}{\log 3}=\frac{1-\log 2}{\log 3}$. Now, plugging in the values yeilds $\boxed{1.47}$.