If x!x!x!x=3, find x.

Since x!x!x!x=3, we know that x3=3. Squaring both sides, we find that 3x=9, so x=93=3.

jmc

algebra intermediate

Problem

x \cdot x \cdot x \cdot x \dots = 3

, find

x

Solution

Since

x \cdot x \cdot x \cdot x \dots = 3

, we know that

x \cdot 3 = 3

. Squaring both sides, we find that

3 x = 9

, so

x = \frac{9}{3} = 3

Final answer