Browse · MATH Print → jmc algebra intermediate Problem The graph of y=ax2+bx+c passes through points (0,5), (1,10), and (2,19). Find a+b+c. Solution — click to reveal Since (1,10) is on the graph, we know that a+b+c=a⋅12+b⋅1+c=10. Final answer 10 ← Previous problem Next problem →