Browse · MATH Print → jmc algebra intermediate Problem Let r, s, and t be the roots of the equation x3−20x2+18x−7=0. Find the value of (1+r)(1+s)(1+t). Solution — click to reveal Expanding, we have (1+r)(1+s)(1+t)=1+(r+s+t)+(rs+st+tr)+rst.By Vieta's formulas, this comes out to 1+20+18+7=46. Final answer 46 ← Previous problem Next problem →