Browse · MATH Print → jmc algebra junior Problem Factor the following expression: 145b2+29b. Solution — click to reveal The greatest common factor of 145b2 and 29b is 29b. We factor 29b out of both terms to get:145b2+29b=29b⋅5b+29b⋅1=29b(5b+1). Final answer 29b(5b+1) ← Previous problem Next problem →