imc

Set the time Ian traveled as $I$, and set Han's speed as $H$. Therefore, Jan's speed is $H+5.$ We get the following equation for how much Han is ahead of Ian: $H+5I=70.$ The expression for how much Jan is ahead of Ian is: $2(H+5)+10I.$ This simplifies to: $2H+10+10I.$ However, this is just $2(H+5I)+10.$ Substitute, from the first equation, $H+5I$ as $70.$ Therefore, the answer is $140+10$, which is $150$, or $\boxed{150}$