Browse · MATH Print → jmc algebra senior Problem If (411)3x−3=51, what is the value of (411)6x+2? Express your answer as a fraction. Solution — click to reveal We rewrite (411)6x+2 and then substitute the given equation: (411)6x+2=(411)6x−6⋅(411)8=((411)3x−3)2⋅(111/4)8=(51)2⋅11(8/4)=251⋅121=25121 Final answer \frac{121}{25} ← Previous problem Next problem →