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jmc

prealgebra junior

Problem

\frac{1}{1 + \frac{1}{2 + \frac{1}{3}}} =

(A)

\frac{1}{6}

(B)

\frac{3}{10}

(C)

\frac{7}{10}

(D)

\frac{5}{6}

Solution

\frac{1}{1 + \frac{1}{2 + \frac{1}{3}}} = \frac{1}{1 + \frac{1}{\frac{7}{3}}} = \frac{1}{1 + \frac{3}{7}} = \frac{1}{\frac{10}{7}} = \frac{7}{10}

Final answer

C