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PrintIranian Mathematical Olympiad
Iran geometry
Problem
Point is the center of the circumcircle of the acute-angled triangle . A circle centered at tangent to side of the triangle is drawn. Let and be the intersection points of tangents from to this circle with side in such a way that points and are on one side of the line . A line parallel to side is drawn from to intersect the tangent at point to the circle at . Similarly, a line parallel to side is drawn from to intersect the tangent at point to the circle at . Prove that line is tangent to .
Solution
Let and be the feet of the perpendicular lines from to and , respectively. Since is a point on the perpendicular bisector of , we have and hence So and hence Therefore, the quadrilateral is cyclic and thus . This implies that is tangent to . By a similar arguments we can prove that is tangent to .
Techniques
TangentsCyclic quadrilateralsTriangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleAngle chasing