Browse · MATH Print → jmc number theory intermediate Problem What is the units digit of 100020⋅21⋅22⋅23⋅24⋅25? Solution — click to reveal 100020⋅21⋅22⋅23⋅24⋅25=23⋅5322⋅5⋅21⋅2⋅11⋅23⋅23⋅3⋅52=23⋅3⋅21⋅11⋅23≡23⋅32(mod10)≡2(mod10). Final answer 2 ← Previous problem Next problem →