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jmc

number theory intermediate

Problem

What is the base ten equivalent of

5432 1_{6}

?

Solution

5432 1_{6} = 5 \cdot 6^{4} + 4 \cdot 6^{3} + 3 \cdot 6^{2} + 2 \cdot 6^{1} + 1 \cdot 6^{0} = 6480 + 864 + 108 + 12 + 1 = 7465

.

Final answer

7465