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Romanian Mathematical Olympiad

Romania geometry

Problem

Consider the cube . The angle bisectors of the angles and meet and at points and , respectively. The point is the foot of the perpendicular from onto while is the foot of the perpendicular from onto . The point is the center of the face . a) Prove that the planes and are parallel. b) Given that , find the distance between the planes and .

problem
Solution
a) Denote by and the intersections of the straight lines and , respectively and . In the triangle , is an angle bisector and an altitude, so . In the triangle , is an angle bisector and an altitude, so . The segment joins the midpoints of two sides of the triangle , hence , and the segment joins the midpoints of two sides of triangle , hence . The requirement follows from the fact that the planes and are the same.



b) The distance between the two planes is equal to the distance from to the plane , and this last distance is half the distance from to the same plane. As the distance from to the plane is , the required distance is .
Final answer
sqrt(2)/4

Techniques

Other 3D problemsTriangles