jmc

Let $a$ be the first term, and let $d$ be the common difference. Then the $n^{\text{th}}$ term is $a+(n-1)d$. In particular, the second term is $a+d=2$, and the ninth term is $a+8d=30$. Subtracting these equations, we get $7d=28$, so $d=4$. Substituting this into the equation $a+d=2$, we get $a+4=2$, so $a=-2$.

Then the fiftieth term is $a+49d=-2+49\cdot 4=\boxed{194}$.