jmc

$\left(\genfrac{}{}{0ex}{}{n}{1}\right)=\frac{n!}{1!(n-1)!}=\boxed{n}$. Also, $\left(\genfrac{}{}{0ex}{}{n}{1}\right)$ is the number of ways to choose 1 object out of $n$. Since there are $n$ different objects, there are $\boxed{n}$ ways to do this.