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Printjmc
counting and probability intermediate
Problem
A standard deck of 52 cards has 13 ranks (Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King) and 4 suits (, , , and ), such that there is exactly one card for any given rank and suit. Two of the suits ( and ) are black and the other two suits ( and ) are red. The deck is randomly arranged. What is the probability that the top three cards are all s?
Solution
There are 13 ways to choose the first card to be a , then 12 ways to choose the second card to be another , then 11 ways to choose the third card to be a . There are ways to choose any three cards. So the probability is .
Final answer
\dfrac{11}{850}