smc

The lines are coplanar, ${\ell }_1\parallel {\ell }_3$, and ${\ell }_1$ intersects ${\ell }_2$. Therefore, ${\ell }_3$ also intersects ${\ell }_2$. The locus of all points equidistant from parallel lines ${\ell }_1$ and ${\ell }_3$ is a third parallel line in between them. Let this line be ${\ell }_4$, and let the distance from ${\ell }_4$ to either ${\ell }_1$ or ${\ell }_3$ be $d$. The points equidistant from lines ${\ell }_1$, ${\ell }_2$, and ${\ell }_3$ must all lie on ${\ell }_4$ and be a distance $d$ from line ${\ell }_2$. There are only 2 points, on either side of ${\ell }_2$, which satisfy these conditions. Thus, our answer is $\boxed{2}$.