jmc

Since $100=50\cdot 2$, there are 50 integers in the set that are divisible by 2. The numbers among these that are also divisible by 3 are the multiples of 6 in the set. Dividing 100 by 6 gives $16\frac{2}{3}$, so there are 16 multiples of 6 in the set, which leaves $50-16=34$ multiples of 2 that are not also multiples of 3. There are 100 numbers in the set so the desired probability is $\frac{34}{100}=\boxed{\frac{17}{50}}$.