jmc

Expanding the left side, we have $x^2+6x+9=121\Rightarrow x^2+6x-112=0$. For a quadratic with the equation $a{x}^2+bx+c=0$, the sum of the roots is $-b/a$. Applying this formula to the problem, we have that the sum of the two roots is $-6/1=\boxed{-6}$.