jmc

We group the terms of the polynomial: $(8x^3+12x^2)+(-2x-3)$. Notice that both pairs of terms are multiples of $2x+3$, so we can factor it out: $(2x+3)(4x^2-1)$. The second expression is a difference of squares, so we can factor it, giving $\boxed{(2x+3)(2x-1)(2x+1)}$.