Browse · MATH Print → jmc algebra junior Problem If x+y=127 and x−y=121, what is the value of x2−y2? Express your answer as a common fraction. Solution — click to reveal x2−y2 factors into (x+y)(x−y), so, to obtain the value of x2−y2, simply multiply 127⋅121 to get 1447. Final answer \frac{7}{144} ← Previous problem Next problem →