Browse · MATH Print → jmc algebra intermediate Problem If A:B:C=2:1:4, what is the value of (3A+2B)÷(4C−A)? Express your answer as a common fraction. Solution — click to reveal Suppose that B=x. Then A=2x and C=4x. Thus (3A+2B)÷(4C−A)=14x8x=148=74. Final answer \frac{4}{7} ← Previous problem Next problem →