Browse · MATH Print → jmc algebra intermediate Problem Simplify: x(3x2−2)−5(x2−2x+7). Express your answer in the form Ax3+Bx2+Cx+D. Solution — click to reveal Using the distributive property and combining like terms: x(3x2−2)−5(x2−2x+7)=3x3−2x−5x2+10x−35=3x3−5x2+8x−35. Final answer 3x^3-5x^2+8x-35 ← Previous problem Next problem →