Evaluate x^2y^3z if x = 13, y = 23, and z = -9.

We have x^2 y^3 z = (13)^2 (23)^3(-9) = 19 827 (-9) = -827(19 9) = -827.

jmc

algebra junior

Problem

Evaluate

x^{2} y^{3} z

x = \frac{1}{3}

y = \frac{2}{3}

, and

z = - 9

Solution

We have

x^{2} y^{3} z = (\frac{1}{3})^{2} (\frac{2}{3})^{3} (- 9) = \frac{1}{9} \cdot \frac{8}{27} \cdot (- 9) = - \frac{8}{27} (\frac{1}{9} \cdot 9) = - \frac{8}{27} .

Final answer

-\frac{8}{27}