Browse · MATH Print → jmc algebra junior Problem If (x,y) is a solution to the system xyx2y+xy2+x+y=6,=63,find x2+y2. Solution — click to reveal The second equation factors as (xy+1)(x+y)=63, so 7(x+y)=63, or x+y=9. Then x2+y2=(x+y)2−2xy=92−2⋅6=69. Final answer 69 ← Previous problem Next problem →