imc

Since $d=rt$, we note that Odell runs one lap in $\frac{2\cdot 50\pi }{250}=\frac{2\pi }{5}$ minutes, while Kershaw also runs one lap in $\frac{2\cdot 60\pi }{300}=\frac{2\pi }{5}$ minutes. They take the same amount of time to run a lap, and since they are running in opposite directions they will meet exactly twice per lap (once at the starting point, the other at the half-way point). Thus, there are $\frac{30}{\frac{2\pi }{5}}\approx 23.8$ laps run by both, or $\lfloor 2\cdot 23.8\rfloor =23\cdot 2+1=\boxed{47}$ meeting points.