Browse · MATH Print → jmc algebra intermediate Problem Let f(x)=Ax−2B2 and g(x)=Bx, where B=0. If f(g(1))=0, what is A in terms of B? Solution — click to reveal First we find that f(g(1))=A(B⋅1)−2B2=AB−2B2. Therefore, we have that AB−2B2=B(A−2B)=0. Since B=0, we have that A−2B=0, and A=2B. Final answer 2B ← Previous problem Next problem →