Browse · MATH Print → jmc algebra junior Problem Factor the following expression: 37a2+111a. Solution — click to reveal The greatest common factor of 37a2 and 111a is 37a. We factor 37a out of both terms to get37a2+111a=37a⋅a+37a⋅3=37a(a+3) Final answer 37a(a+3) ← Previous problem Next problem →