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smc

prealgebra intermediate

Problem

After rationalizing the numerator of

\frac{3 - 2}{3}

, the denominator in simplest form is:

(A)

s q r t (3) (s q r t (3) + s q r t (2))

(B)

s q r t (3) (s q r t (3) - s q r t (2))

(C)

3 - s q r t (3) s q r t (2)

(D)

3 + s q r t (6)

Solution

To rationalize the numerator, multiply by the conjugate.

\frac{3 - 2}{3} \cdot \frac{3 + 2}{3 + 2} = \frac{1}{3 + 6} .

The denominator is

3 + 6 .

Final answer

D