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Printsmc
prealgebra intermediate
Problem
If is divided into three parts proportional to , , and , the smallest part is:
(A)
(B)
(C)
(D)
Solution
If the three numbers are in proportion to , then they should also be in proportion to . This implies that the three numbers can be expressed as , , and . Add these values together to get: Divide each side by 6 and get that which is .
Final answer
C