If _6 x=2.5, the value of x is:

_6 x=52 2_6 x=5 _6 x^2=5 x^2=6^5 x=366, 366

smc

algebra intermediate

Problem

lo g_{6} x = 2.5

, the value of

x

is:

(A)

90

(B)

36

(C)

366

(D)

0.5

Solution

lo g_{6} x = \frac{5}{2} ⟹ 2 lo g_{6} x = 5 ⟹ lo g_{6} x^{2} = 5 ⟹ x^{2} = 6^{5} ⟹ x = 366

366

Final answer